(9x+5)(2x^2-5x-3)=0

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Solution for (9x+5)(2x^2-5x-3)=0 equation: 


Simplifying
(9x + 5)(2x2 + -5x + -3) = 0

Reorder the terms:
(5 + 9x)(2x2 + -5x + -3) = 0

Reorder the terms:
(5 + 9x)(-3 + -5x + 2x2) = 0

Multiply (5 + 9x) * (-3 + -5x + 2x2)
(5(-3 + -5x + 2x2) + 9x * (-3 + -5x + 2x2)) = 0
((-3 * 5 + -5x * 5 + 2x2 * 5) + 9x * (-3 + -5x + 2x2)) = 0
((-15 + -25x + 10x2) + 9x * (-3 + -5x + 2x2)) = 0
(-15 + -25x + 10x2 + (-3 * 9x + -5x * 9x + 2x2 * 9x)) = 0
(-15 + -25x + 10x2 + (-27x + -45x2 + 18x3)) = 0

Reorder the terms:
(-15 + -25x + -27x + 10x2 + -45x2 + 18x3) = 0

Combine like terms: -25x + -27x = -52x
(-15 + -52x + 10x2 + -45x2 + 18x3) = 0

Combine like terms: 10x2 + -45x2 = -35x2
(-15 + -52x + -35x2 + 18x3) = 0

Solving
-15 + -52x + -35x2 + 18x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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